4.9x^2=60

Solution for 4.9x^2=60 equation:

4.9x^2=60

We move all terms to the left:

4.9x^2-(60)=0

a = 4.9; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·4.9·(-60)
Δ = 1176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1176}=\sqrt{196*6}=\sqrt{196}*\sqrt{6}=14\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{6}}{2*4.9}=\frac{0-14\sqrt{6}}{9.8}
=-\frac{14\sqrt{6}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{6}}{2*4.9}=\frac{0+14\sqrt{6}}{9.8}
=\frac{14\sqrt{6}}{9.8}
$